题目内容
9×9-1=80 (10-1)÷9=1
98×9-2=880 (200-2)÷9=22
987×9-3=8880 (3000-3)÷9=333
9876×9-4=
98765×9-5=
98×9-2=880 (200-2)÷9=22
987×9-3=8880 (3000-3)÷9=333
9876×9-4=
88880
88880
(40000-4)÷9=4444
4444
98765×9-5=
888880
888880
(500000-5)÷9=55555
55555
.分析:(1)9乘9减1等于80,98乘9减去2等于880,987乘9减去3=8880,…,得出“式”的规律9876…(10-n)×9-n=888…80(n个8加上0);
(2)十减去1再除以9等于1,2百减2在除以9等于22,3千减3再除以9等于333,…得出“式”的规律n×10n-n然后再除以9得n×111…1(n个1);直接得解.
(2)十减去1再除以9等于1,2百减2在除以9等于22,3千减3再除以9等于333,…得出“式”的规律n×10n-n然后再除以9得n×111…1(n个1);直接得解.
解答:解:(1)由9×9-1=80,98×9-2=880,987×9-3=8880得出“式”的规律9876…(10-n)×9-n=888…80(n个8加上0);
所以9876×9-4=88880,98765×9-5=888880;
(2)由(10-1)÷9=1,(200-2)÷9=22,(3000-3)÷9=333,得出“式”的规律n×10n-n然后再除以9得n×111…1(n个1),
所以(40000-4)÷9=4444,(500000-5)÷9=55555;
故答案为:88880,888880,4444,55555.
所以9876×9-4=88880,98765×9-5=888880;
(2)由(10-1)÷9=1,(200-2)÷9=22,(3000-3)÷9=333,得出“式”的规律n×10n-n然后再除以9得n×111…1(n个1),
所以(40000-4)÷9=4444,(500000-5)÷9=55555;
故答案为:88880,888880,4444,55555.
点评:认真分析,找出规律是解决此题的关键.
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