题目内容
阅读模仿题
(1)规定一种运算“*”,符合a*b=(a×b)÷(a+b)
例1:3*5=(3×5)÷(3+5)=
请你计算:①4*2 ②(4*2)*3
(2)例2:计算
+
+
+------+
可按如下方法计算
解:原式=
× (
-
+
-
+
-
+------+
-
)
=
×(1-
)
=
×
=
请你计算:
+
+
+------+
.
(1)规定一种运算“*”,符合a*b=(a×b)÷(a+b)
例1:3*5=(3×5)÷(3+5)=
15 |
8 |
请你计算:①4*2 ②(4*2)*3
(2)例2:计算
1 |
1×3 |
1 |
3×5 |
1 |
5×7 |
1 |
1999×2001 |
解:原式=
1 |
2 |
1 |
1 |
1 |
3 |
1 |
3 |
1 |
5 |
1 |
5 |
1 |
7 |
1 |
1999 |
1 |
2001 |
=
1 |
2 |
1 |
2001 |
=
1 |
2 |
2000 |
2001 |
=
1000 |
2001 |
请你计算:
1 |
2×4 |
1 |
4×6 |
1 |
6×8 |
1 |
2000×2002 |
分析:(1)规定一种运算“*”,符合a*b=(a×b)÷(a+b),模仿例题,代入数值,即可得解.
(2)模仿例题2,
=
×(
-
)以此类推,
=
×(
-
),依次展开,中间部分抵消,即可得解.
(2)模仿例题2,
1 |
2×4 |
1 |
2 |
1 |
2 |
1 |
4 |
1 |
2000×2002 |
1 |
2 |
1 |
2000 |
1 |
2002 |
解答:解:(1)①4*2,
=(4×2)÷(4+2),
=
;
②(4*2)*3,
=
*3,
=(
×3)÷(
+3),
=4÷
,
=4×
,
=
;
(2)
+
+
+…+
,
=
×(
-
+
-
+
-
+…+
-
),
=
×(
-
),
=
×
,
=
,
=
.
=(4×2)÷(4+2),
=
4 |
3 |
②(4*2)*3,
=
4 |
3 |
=(
4 |
3 |
4 |
3 |
=4÷
13 |
3 |
=4×
3 |
13 |
=
12 |
13 |
(2)
1 |
2×4 |
1 |
4×6 |
1 |
6×8 |
1 |
2000×2002 |
=
1 |
2 |
1 |
2 |
1 |
4 |
1 |
4 |
1 |
6 |
1 |
6 |
1 |
8 |
1 |
2000 |
1 |
2002 |
=
1 |
2 |
1 |
2 |
1 |
2002 |
=
1 |
2 |
1000 |
2002 |
=
500 |
2002 |
=
250 |
1001 |
点评:此题考查了算术中的规律,模仿例题,代入数值,即可得解.
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