题目内容
递等式计算
(35.55)×15
8×7×125
5.3+43.6+38.7
(59+187)÷3.
(35.55)×15
8×7×125
5.3+43.6+38.7
(59+187)÷3.
分析:整数或小数的四则混合运算顺序,先算乘除,后算加减,有括号的,先算括号内的部分;即可得解.
解答:解:(1)(35+55)×15,
=90×15,
=1350;
(2)8×7×125,
=(8×125)×7,
=1000×7,
=7000;
(3)5.3+43.6+38.7,
=(5.3+38.7)+43.6,
=44+43.6,
=87.6;
(4)(59+187)÷3,
=246÷3,
=82.
=90×15,
=1350;
(2)8×7×125,
=(8×125)×7,
=1000×7,
=7000;
(3)5.3+43.6+38.7,
=(5.3+38.7)+43.6,
=44+43.6,
=87.6;
(4)(59+187)÷3,
=246÷3,
=82.
点评:此题考查了整数和小数的四则混合运算,锻炼了学生的计算能力,注意能简便计算的,要简便计算.

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