题目内容

用递等式计算.(可用简便算法)
57
10
×
3
10
+
3
10
×
3
10

2
3
+(
4
7
+
1
2
)×
7
25

8
13
÷7+
1
7
×
6
13

8
13
÷7+
1
7
×
7
13

1
12
+
1
2
-
7
12
)÷
1
7

1
1
5
÷0.24-1.6×
3
4
分析:(1)运用乘法分配律简算;
(2)先算小括号里面的加法,再算括号外的乘法,最后算括号外的加法;
(3)(4)先把乘法变成乘法,再运用乘法分配律简算;
(5)先计算小括号里面的加减法,再算括号外的除法;
(6)先同时运算除法和乘法,再算减法.
解答:解:(1)
57
10
×
3
10
+
3
10
×
3
10

=(
57
10
+
3
10
)×
3
10

=6×
3
10

=
9
5


(2)
2
3
+(
4
7
+
1
2
)×
7
25

=
2
3
+
15
14
×
7
25

=
2
3
+
3
10

=
29
30


(3)
8
13
÷7+
1
7
×
6
13

=
8
13
×
1
7
+
1
7
×
6
13

=(
8
13
+
6
13
)×
1
7

=
14
13
×
1
7

=
2
13


(4)
8
13
÷7+
1
7
×
7
13

=
8
13
×
1
7
+
1
7
×
7
13

=(
8
13
+
7
13
)×
1
7

=
15
13
×
1
7

=
15
91


(5)(
1
12
+
1
2
-
7
12
)÷
1
7

=(
7
12
-
7
12
)÷
1
7

=0÷
1
7

=0;

(6)1
1
5
÷0.24-1.6×
3
4

=5-1.2,
=3.8.
点评:本题考查了四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律进行简便计算.
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