题目内容
用递等式计算.(可用简便算法)
×
+
×
+(
+
)×
÷7+
×
÷7+
×
(
+
-
)÷
1
÷0.24-1.6×
.
57 |
10 |
3 |
10 |
3 |
10 |
3 |
10 |
2 |
3 |
4 |
7 |
1 |
2 |
7 |
25 |
8 |
13 |
1 |
7 |
6 |
13 |
8 |
13 |
1 |
7 |
7 |
13 |
(
1 |
12 |
1 |
2 |
7 |
12 |
1 |
7 |
1
1 |
5 |
3 |
4 |
分析:(1)运用乘法分配律简算;
(2)先算小括号里面的加法,再算括号外的乘法,最后算括号外的加法;
(3)(4)先把乘法变成乘法,再运用乘法分配律简算;
(5)先计算小括号里面的加减法,再算括号外的除法;
(6)先同时运算除法和乘法,再算减法.
(2)先算小括号里面的加法,再算括号外的乘法,最后算括号外的加法;
(3)(4)先把乘法变成乘法,再运用乘法分配律简算;
(5)先计算小括号里面的加减法,再算括号外的除法;
(6)先同时运算除法和乘法,再算减法.
解答:解:(1)
×
+
×
,
=(
+
)×
,
=6×
,
=
;
(2)
+(
+
)×
,
=
+
×
,
=
+
,
=
;
(3)
÷7+
×
,
=
×
+
×
,
=(
+
)×
,
=
×
,
=
;
(4)
÷7+
×
,
=
×
+
×
,
=(
+
)×
,
=
×
,
=
;
(5)(
+
-
)÷
,
=(
-
)÷
,
=0÷
,
=0;
(6)1
÷0.24-1.6×
,
=5-1.2,
=3.8.
57 |
10 |
3 |
10 |
3 |
10 |
3 |
10 |
=(
57 |
10 |
3 |
10 |
3 |
10 |
=6×
3 |
10 |
=
9 |
5 |
(2)
2 |
3 |
4 |
7 |
1 |
2 |
7 |
25 |
=
2 |
3 |
15 |
14 |
7 |
25 |
=
2 |
3 |
3 |
10 |
=
29 |
30 |
(3)
8 |
13 |
1 |
7 |
6 |
13 |
=
8 |
13 |
1 |
7 |
1 |
7 |
6 |
13 |
=(
8 |
13 |
6 |
13 |
1 |
7 |
=
14 |
13 |
1 |
7 |
=
2 |
13 |
(4)
8 |
13 |
1 |
7 |
7 |
13 |
=
8 |
13 |
1 |
7 |
1 |
7 |
7 |
13 |
=(
8 |
13 |
7 |
13 |
1 |
7 |
=
15 |
13 |
1 |
7 |
=
15 |
91 |
(5)(
1 |
12 |
1 |
2 |
7 |
12 |
1 |
7 |
=(
7 |
12 |
7 |
12 |
1 |
7 |
=0÷
1 |
7 |
=0;
(6)1
1 |
5 |
3 |
4 |
=5-1.2,
=3.8.
点评:本题考查了四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律进行简便计算.
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