题目内容
计算.能简算的要简算.
25×1.25×32 | (3.75+4.1+2.35)×9.8 | 12×(
| ||||||||||||||||
(20.2×0.4+7.88)÷4.2 | (
|
10÷[
|
分析:(1)25×1.25×32把32拆成4×8,利用乘法的结合律变成(25×4)×(1.25×8)计算简便;
(2)(3.75+4.1+2.35)×9.8把括号里的((3.75+4.1+2.35)变成[(3.75+2.35)+4.1]=6.1+4.1=10.2,再把9.8变成(10-0.2)平方差公式变成(10+0.2)×(10-0.2)计算;
(3)12×(
+
-
)利用乘法的结合律变成12×
+12×
-12×
计算简便;
(4)(20.2×0.4+7.88)÷4.2利用四则运算的顺序,先算括号里的20.2×0.4再算括号里的加,最后算除;
(5)(
+
)÷
+
利用四则运算的顺序,先算括号里的加再算括号外的除,最后算加;
(6)10÷[
-(
÷
+
)]先算括号里的除再算括号里的加,然后算中括号里面的减法,最后算括号外面的除.
(2)(3.75+4.1+2.35)×9.8把括号里的((3.75+4.1+2.35)变成[(3.75+2.35)+4.1]=6.1+4.1=10.2,再把9.8变成(10-0.2)平方差公式变成(10+0.2)×(10-0.2)计算;
(3)12×(
1 |
4 |
1 |
6 |
1 |
3 |
1 |
4 |
1 |
6 |
1 |
3 |
(4)(20.2×0.4+7.88)÷4.2利用四则运算的顺序,先算括号里的20.2×0.4再算括号里的加,最后算除;
(5)(
1 |
5 |
1 |
4 |
7 |
3 |
7 |
10 |
(6)10÷[
8 |
3 |
5 |
13 |
5 |
26 |
2 |
5 |
解答:解:(1)25×1.25×32,
=(25×4)×(1.25×8),
=100×10,
=1000;
(2)(3.75+4.1+2.35)×9.8,
=[(3.75+2.35)+4.1]×9.8,
=[6.1+4.1]]×9.8,
=(10+0.2)×(10-0.2),
=100-0.04,
=99.96;
(3)12×(
+
-
),
=12×
+12×
-12×
,
=3+2-4,
=1;
(5)(
+
)÷
+
,
=
×
+
,
=
+
,
=
;
(6)10÷[
-(
÷
+
)],
=10÷[
-(2+
)]
=10÷[
-
],
=10÷
,
=
.
=(25×4)×(1.25×8),
=100×10,
=1000;
(2)(3.75+4.1+2.35)×9.8,
=[(3.75+2.35)+4.1]×9.8,
=[6.1+4.1]]×9.8,
=(10+0.2)×(10-0.2),
=100-0.04,
=99.96;
(3)12×(
1 |
4 |
1 |
6 |
1 |
3 |
=12×
1 |
4 |
1 |
6 |
1 |
3 |
=3+2-4,
=1;
(5)(
1 |
5 |
1 |
4 |
7 |
3 |
7 |
10 |
=
9 |
20 |
3 |
7 |
7 |
10 |
=
27 |
140 |
98 |
140 |
=
25 |
28 |
(6)10÷[
8 |
3 |
5 |
13 |
5 |
26 |
2 |
5 |
=10÷[
8 |
3 |
2 |
5 |
=10÷[
8 |
3 |
12 |
5 |
=10÷
4 |
15 |
=
75 |
2 |
点评:考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算律简便计算.
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