题目内容
递等式计算
0.7+9.6×0.25 | (2.44-1.8)÷0.4×2.5 |
23.4-0.8-13.4-7.2 | [3.2-3.2×(30.4-29.85)]÷1.8. |
分析:(1)先算乘法,再算加法;
(2)先算减法,再算除法,最后算乘法;
(3)根据连减的性质进行计算;
(4)先算小括号里面的减法,再算中括号里面的乘法,再算中括号里面的减法,最后算除法.
(2)先算减法,再算除法,最后算乘法;
(3)根据连减的性质进行计算;
(4)先算小括号里面的减法,再算中括号里面的乘法,再算中括号里面的减法,最后算除法.
解答:解:(1)0.7+9.6×0.25,
=0.7+2.4,
=3.1;
(2)(2.44-1.8)÷0.4×2.5,
=0.64÷0.4×2.5,
=1.6×2.5,
=4;
(3)23.4-0.8-13.4-7.2,
=(23.4-13.4)-(0.8+7.2),
=10-8,
=2;
(4)[3.2-3.2×(30.4-29.85)]÷1.8,
=[3.2-3.2×0.55]÷1.8,
=[3.2-1.76]÷1.8,
=1.44÷1.8,
=0.8.
=0.7+2.4,
=3.1;
(2)(2.44-1.8)÷0.4×2.5,
=0.64÷0.4×2.5,
=1.6×2.5,
=4;
(3)23.4-0.8-13.4-7.2,
=(23.4-13.4)-(0.8+7.2),
=10-8,
=2;
(4)[3.2-3.2×(30.4-29.85)]÷1.8,
=[3.2-3.2×0.55]÷1.8,
=[3.2-1.76]÷1.8,
=1.44÷1.8,
=0.8.
点评:四则运算,先弄清运算顺序,然后再进一步计算,能简算的要简算.
练习册系列答案
相关题目
递等式计算
0.7+9.6×0.25 | (2.44-1.8)÷0.4×2.5 |
23.4-0.8-13.4-7.2 | [3.2-3.2×(30.4-29.85)]÷1.8. |