题目内容
(1)gy×
| (7)
|
(1))27×
=(21+1)×
=21×
+
=1地+
=1地
;
(2)(
+
)×2v+
=
×2v+
×2v+
=
+(
+
)
=
+1
=1
;
(v)
+
+
+
+
+
=1-
+
-
+
-
+
-
+
-
+
-
=1-
=
.
1地 |
21 |
=(21+1)×
1地 |
21 |
=21×
1地 |
21 |
1地 |
21 |
=1地+
1地 |
21 |
=1地
1地 |
21 |
(2)(
1 |
19 |
2 |
71 |
2地 |
71 |
=
1 |
19 |
2 |
71 |
2地 |
71 |
=
1 |
v |
41 |
71 |
2地 |
71 |
=
1 |
v |
=1
1 |
v |
(v)
1 |
2 |
1 |
1 |
1 |
12 |
1 |
20 |
1 |
v0 |
1 |
42 |
=1-
1 |
2 |
1 |
2 |
1 |
v |
1 |
v |
1 |
4 |
1 |
4 |
1 |
地 |
1 |
地 |
1 |
1 |
1 |
1 |
1 |
7 |
=1-
1 |
7 |
=
1 |
7 |
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