题目内容

15.用简便方法计算
3600000÷125÷32÷25
1.25×3.28+12.5×0.241+125×0.0431
999×27-333×51+666×35
64×12.5×0.25×0.05.

分析 (1)根据除法的性质得到原式=3600000÷(125×32×25),再变形为3600000÷[(125×8)×(4×25)]简便计算即可求解;
(2)根据积不变规律得到原式=1.25×3.28+1.25×2.41+1.25×4.31,再根据乘法分配律简便计算;
(3)根据积不变规律得到原式=333×81-333×51+333×70,再根据乘法分配律简便计算;
(4)变形为(8×12.5)×(4×0.25)×(2×0.05)简便计算即可求解.

解答 解:(1)3600000÷125÷32÷25
=3600000÷(125×32×25)
=3600000÷[(125×8)×(4×25)]
=3600000÷(1000×100)
=3600000÷100000
=36

(2)1.25×3.28+12.5×0.241+125×0.0431
=1.25×3.28+1.25×2.41+1.25×4.31
=1.25×(3.28+2.41+4.31)
=1.25×10
=12.5

(3)999×27-333×51+666×35
=333×81-333×51+333×70
=333×(81-51+70)
=333×100
=33300

(4)64×12.5×0.25×0.05
=(8×12.5)×(4×0.25)×(2×0.05)
=100×1×0.1
=10

点评 考查了小数的巧算,小数“巧”算的基本途径还是灵活应用小数四则运算的法则、运算定律,使题目中的数尽可能转化为整数.在某种意义上讲,“化整”是小数运算技巧的灵魂.

练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网