题目内容

下面各题怎样简便就怎样算.
25×13×4135+39+55+6135×201
2000÷25÷817×43-43×7278-122-78.

解:(1)25×13×4,
=25×4×13,
=100×13,
=1300;

(2)135+39+55+61,
=(135+55)+(39+61),
=190+100,
=290;

(3)35×201,
=35×(200+1),
=35×200+35×1,
=7000+35,
=7035;

(4)2000÷25÷8,
=2000÷(25×8),
=2000÷200,
=10;

(5)17×43-43×7,
=(17-7)×43,
=10×43,
=430;

(6)278-122-78,
=278-(122+78),
=278-200,
=78.
分析:(1)根据乘法交换律进行计算;
(2)根据加法交换律和结合律进行计算;
(3)根据乘法分配律进行计算;
(4)根据连除的性质进行计算;
(5)根据乘法分配律进行计算;
(6)根据连减的性质进行计算.
点评:四则运算,先弄清运算顺序,然后再进一步计算,能简算的要简算.
练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网