题目内容
在下面方框里分别填上不同的最简分数,使算式的结果都是
,并写出计算过程
(1)□+□
(2)□÷□
解:(1)因为:
=
=
=
+
,
所以
+
=
;
(2)因为:
×
=
,
所以
=
;
故答案为:
+
=
,
=
(答案不唯一).
分析:(1)可以利用分数的基本性质,把
的分子分母同时扩大相同的倍数,比如3倍,这个分数变成了
,再把分子3拆成两个数的和,变成同分母的两个分数即
+
(答案不唯一);
(2)根据□÷□=
,可以假设除数为
,被除数是
×
=
(答案不唯一).
点评:问题一,主要利用分数的基本性质拆项解答;问题二,主要利用被除数、除数、商三者之间的关系解答.

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
所以
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
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(2)因为:



所以
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

故答案为:






分析:(1)可以利用分数的基本性质,把




(2)根据□÷□=

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
点评:问题一,主要利用分数的基本性质拆项解答;问题二,主要利用被除数、除数、商三者之间的关系解答.

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