题目内容
(2012?潍坊模拟)
计算 ①35×
|
②8.75×2
| ||||||||||||
③
|
④
|
分析:①运用乘法的结合律,交换律进行计算即可.
②把87
改写成8.75×10,然后运用乘法的分配律进行计算即可.
③按照分数四则混合运算的剩下进行计算,先计算括号内部的,再就是括号外面的.
④把
÷23改写成
×
,然后运用乘法的分配律进行计算即可.
②把87
1 |
2 |
③按照分数四则混合运算的剩下进行计算,先计算括号内部的,再就是括号外面的.
④把
8 |
17 |
8 |
17 |
1 |
23 |
解答:解:①35×
×24×
,
=(35×
)×(
×24),
=5×4,
=20;
②8.75×2
+8.75×7
+87
,
=8.75×2
+8.75×7
+8.75×10,
=8.75×(2
+7
+10),
=8.75×20,
=175;
③
×{1-(
-
)},
=
×{1-(
-
)},
=
×{1-
}
=
×
,
=
;
④
÷23+
×
,
=
×
+
×
,
=
×(
+
),
=
;
1 |
6 |
1 |
7 |
=(35×
1 |
7 |
1 |
6 |
=5×4,
=20;
②8.75×2
4 |
5 |
1 |
5 |
1 |
2 |
=8.75×2
4 |
5 |
1 |
5 |
=8.75×(2
4 |
5 |
1 |
5 |
=8.75×20,
=175;
③
4 |
29 |
3 |
4 |
3 |
8 |
=
4 |
29 |
6 |
8 |
3 |
8 |
=
4 |
29 |
3 |
8 |
=
4 |
29 |
5 |
8 |
=
5 |
58 |
④
8 |
17 |
1 |
23 |
9 |
17 |
=
8 |
17 |
1 |
23 |
1 |
23 |
9 |
17 |
=
1 |
23 |
8 |
17 |
9 |
17 |
=
1 |
23 |
点评:考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算律简便计算.
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