题目内容
(2012?武定县模拟)混合运算.(能简算的要简算)
45×102=
×40-
÷
=
7.85-1.89-2.11+2.15=
3450+450÷18×15=
40÷[(
-
)×3]=
168.8÷(24.3×2-6.4)=
45×102=
4590
4590
;7 |
16 |
5 |
16 |
1 |
40 |
5
5
; 7.85-1.89-2.11+2.15=
6
6
;3450+450÷18×15=
3825
3825
; 40÷[(
3 |
4 |
1 |
3 |
32
32
;168.8÷(24.3×2-6.4)=
4
4
.分析:(1)可将102拆分为100+2后根据乘法分配律计算;
(2)可根据乘法分配律计算;
(3)可根据加法交换律及一个数减两个数,等于用这个数减去这两个数的和的减法性质计算;
(4)(5)(6)根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的.
(2)可根据乘法分配律计算;
(3)可根据加法交换律及一个数减两个数,等于用这个数减去这两个数的和的减法性质计算;
(4)(5)(6)根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的.
解答:解:(1)45×102
=45×(100+2),
=45×100+45×2,
=4500+90,
=4590;
(2)
×40-
÷
=
×40-
×40,
=(
-
)×40,
=
×40,
=5;
(3)7.85-1.89-2.11+2.15
=7.85+2.15-(1.89+2.11),
=10-4,
=6;
(4)3450+450÷18×15
=3450+25×15,
=3450+375,
=3825;
(5)40÷[(
-
)×3]
=40÷[
×3],
=40×
,
=32;
(6)168.8÷(24.3×2-6.4)
=168.8÷(48.6-6.4),
=168.8÷42.2,
=4.
故答案为:4590,5,6,3825,32,4.
=45×(100+2),
=45×100+45×2,
=4500+90,
=4590;
(2)
7 |
16 |
5 |
16 |
1 |
40 |
=
7 |
16 |
5 |
16 |
=(
7 |
16 |
5 |
16 |
=
1 |
8 |
=5;
(3)7.85-1.89-2.11+2.15
=7.85+2.15-(1.89+2.11),
=10-4,
=6;
(4)3450+450÷18×15
=3450+25×15,
=3450+375,
=3825;
(5)40÷[(
3 |
4 |
1 |
3 |
=40÷[
5 |
12 |
=40×
4 |
5 |
=32;
(6)168.8÷(24.3×2-6.4)
=168.8÷(48.6-6.4),
=168.8÷42.2,
=4.
故答案为:4590,5,6,3825,32,4.
点评:完成本题要注意分析式中数据的特点及内在联系,然后运用合适的方法进行计算.
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