题目内容
(2008?高邮市)脱式计算:
(1)(3.8-1.8÷2)×0.5
(2)
+
÷
-
(3)
÷[
×(
×
)].
(1)(3.8-1.8÷2)×0.5
(2)
1 |
2 |
9 |
20 |
9 |
10 |
5 |
8 |
(3)
9 |
10 |
1 |
2 |
6 |
5 |
3 |
10 |
分析:本题根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的.
解答:解:(1)(3.8-1.8÷2)×0.5,
=(3.8-0.9)×0.5,
=2.9×0.5,
=1.45;
(2)
+
÷
-
,
=
+
×
-
,
=
+
-
,
=1-
,
=
;
(3)
÷[
×(
×
)],
=
÷[
×
],
=
÷
,
=
×
,
=5.
=(3.8-0.9)×0.5,
=2.9×0.5,
=1.45;
(2)
1 |
2 |
9 |
20 |
9 |
10 |
5 |
8 |
=
1 |
2 |
9 |
20 |
10 |
9 |
5 |
8 |
=
1 |
2 |
1 |
2 |
5 |
8 |
=1-
5 |
8 |
=
3 |
8 |
(3)
9 |
10 |
1 |
2 |
6 |
5 |
3 |
10 |
=
9 |
10 |
1 |
2 |
9 |
25 |
=
9 |
10 |
9 |
50 |
=
9 |
10 |
50 |
9 |
=5.
点评:当算式中同时含有中括号与小括号时,要先算小括号里面的,再算中括号里面的.
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