题目内容
脱式计算: -10+8÷(-2)2-(-4)×3= |
3
| ||||||||
100×(0.7-
|
-49+2×(-3)2+(-6)÷(-
|
分析:本题根据负数加法与减法、乘法与除法的运算法则及四则混合运算的运算顺序计算即可.
解答:解:(1)-10+8÷(-2)2-(-4)×3
=-10+8÷4-(-12),
=-10+2+12,
=4;
(2)3
+(-2
)+5
+(-8
)
=3
-2
+5
-8
,
=(3
+5
)-(2
+8
),
=9-11,
=-2;
(3)100×(0.7-
-
+0.03)
=100×(0.7-0.3-0.16+0.03),
=100×0.27,
=27;
(4)-49+2×(-3)2+(-6)÷(-
)
=-49+2×9+54,
=-49+18+54,
=23.
=-10+8÷4-(-12),
=-10+2+12,
=4;
(2)3
1 |
4 |
3 |
5 |
3 |
4 |
2 |
5 |
=3
1 |
4 |
3 |
5 |
3 |
4 |
2 |
5 |
=(3
1 |
4 |
3 |
4 |
3 |
5 |
2 |
5 |
=9-11,
=-2;
(3)100×(0.7-
3 |
10 |
4 |
25 |
=100×(0.7-0.3-0.16+0.03),
=100×0.27,
=27;
(4)-49+2×(-3)2+(-6)÷(-
1 |
9 |
=-49+2×9+54,
=-49+18+54,
=23.
点评:两个负数相乘或相除之后是正数,只有一个负数一个整数相乘或相除,结果为负数;加负数等于减对应的正数,减负数等于加对应的正数.
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