题目内容
637-201.
解:637-201,
=637-(200+1),
=637-200-1,
=437-1,
=436.
分析:先把201分解成200+1,然后根据减去两个数的和等于连续减去这两个数简算.
点评:本题采取凑整法进行简算,先把接近整十、整百、整千的数看成整十、整百、整千数与另一个数的和或差,进而采用运算定律求解.
=637-(200+1),
=637-200-1,
=437-1,
=436.
分析:先把201分解成200+1,然后根据减去两个数的和等于连续减去这两个数简算.
点评:本题采取凑整法进行简算,先把接近整十、整百、整千的数看成整十、整百、整千数与另一个数的和或差,进而采用运算定律求解.
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