题目内容
(2011?嘉兴模拟)用递等式计算.
(1)
÷[
×(
+
)]
(2)1.05×(3.8-0.8)÷6.3.
(1)
9 |
20 |
1 |
2 |
2 |
5 |
4 |
5 |
(2)1.05×(3.8-0.8)÷6.3.
分析:此题考查在混合运算中有括号时,要先算括号里面的,再算括号外面的.
解答:解:(1)
÷〔
×(
+
)〕,
=
÷〔
×
〕,
=
×
,
=
;
(2)1.05×(3.8-0.8)÷6.3,
=1.05×3÷6.3,
=4.15÷6.3,
=
.
9 |
20 |
1 |
2 |
2 |
5 |
4 |
5 |
=
9 |
20 |
1 |
2 |
6 |
5 |
=
9 |
20 |
5 |
3 |
=
3 |
4 |
(2)1.05×(3.8-0.8)÷6.3,
=1.05×3÷6.3,
=4.15÷6.3,
=
83 |
126 |
点评:解决关键是在混合运算中,要按照运算顺序进行计算.
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