题目内容
计算.能简便的用简便方法计算.
(
+
)×35;
×
+
×
-
;
5×[1.5×(1.07+1.93)];
(19+192)×0.01;
+
×(
-
);
(333+667)÷[25×(23-15)].
(
2 |
7 |
1 |
5 |
3 |
13 |
4 |
5 |
10 |
13 |
4 |
5 |
4 |
5 |
5×[1.5×(1.07+1.93)];
(19+192)×0.01;
1 |
12 |
11 |
12 |
5 |
2 |
1 |
3 |
(333+667)÷[25×(23-15)].
考点:整数、分数、小数、百分数四则混合运算,运算定律与简便运算,小数四则混合运算
专题:运算顺序及法则,运算定律及简算
分析:①②运用乘法分配律简算.
③先算小括号内的,再算中括号内的,最后算括号外的.
④括号内运用乘法分配律计算,最后算括号外的乘法.
⑤先算括号内的,再算括号外的乘法,最后算加法.
⑥先算小括号内的,再算中括号内的,最后算除法.
③先算小括号内的,再算中括号内的,最后算括号外的.
④括号内运用乘法分配律计算,最后算括号外的乘法.
⑤先算括号内的,再算括号外的乘法,最后算加法.
⑥先算小括号内的,再算中括号内的,最后算除法.
解答:
解:①(
+
)×35
=
×35+
×35
=10+7
=17
②
×
+
×
-
=(
+
-1)×
=0×
=0
③5×[1.5×(1.07+1.93)]
=5×[1.5×3]
=5×4.5
=22.5
④(19+192)×0.01
=19×(1+19)×0.01
=19×20×0.01
=3.8
⑤
+
×(
-
)
=
+
×
=
+
=
⑥(333+667)÷[25×(23-15)]
=1000÷[25×8]
=1000÷200
=5
2 |
7 |
1 |
5 |
=
2 |
7 |
1 |
5 |
=10+7
=17
②
3 |
13 |
4 |
5 |
10 |
13 |
4 |
5 |
4 |
5 |
=(
3 |
13 |
10 |
13 |
4 |
5 |
=0×
4 |
5 |
=0
③5×[1.5×(1.07+1.93)]
=5×[1.5×3]
=5×4.5
=22.5
④(19+192)×0.01
=19×(1+19)×0.01
=19×20×0.01
=3.8
⑤
1 |
12 |
11 |
12 |
5 |
2 |
1 |
3 |
=
1 |
12 |
11 |
12 |
13 |
6 |
=
1 |
12 |
143 |
72 |
=
149 |
72 |
⑥(333+667)÷[25×(23-15)]
=1000÷[25×8]
=1000÷200
=5
点评:此题考查了运算定律与简便运算,四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律简便计算.
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