题目内容
(2006?万安县)解方程.
X÷
=36
0.5X+
X=60%
17-120%X=5
×
-
X=
.
X÷
4 |
9 |
0.5X+
1 |
4 |
17-120%X=5
4 |
5 |
1 |
4 |
1 |
2 |
1 |
20 |
分析:(1)根据等式的性质,方程两边同时乘
,即可解答;
(2)先化简0.5X+
X,再根据等式的性质,方程两边同时乘
,即可解答;
(3)根据等式的性质,方程两边同时加上1.2x,然后再同时减去5,最后方程两边同时除以1.2,即可解答;
(4)先化简
×
=
,再根据等式的性质,方程两边同时加上
x,然后再同时减去
,最后方程两边再同时乘2,即可解答.
4 |
9 |
(2)先化简0.5X+
1 |
4 |
4 |
3 |
(3)根据等式的性质,方程两边同时加上1.2x,然后再同时减去5,最后方程两边同时除以1.2,即可解答;
(4)先化简
4 |
5 |
1 |
4 |
1 |
5 |
1 |
2 |
1 |
20 |
解答:解:(1)X÷
=36,
X÷
×
=36×
,
X=16;
(2)0.5X+
X=60%,
X=0.6,
X×
=0.6×
,
X=0.8;
(3)17-120%X=5,
17-1.2X+1.2X=5+1.2X,
5+1.2X-5=17-5,
1.2X=12,
1.2X÷1.2=12÷1.2,
X=10;
(4)
×
-
x=
,
-
x=
,
-
x+
x=
+
x,
+
x=
,
+
x-
=
-
,
x=
,
x×2=
×2,
x=
.
4 |
9 |
X÷
4 |
9 |
4 |
9 |
4 |
9 |
X=16;
(2)0.5X+
1 |
4 |
3 |
4 |
3 |
4 |
4 |
3 |
4 |
3 |
X=0.8;
(3)17-120%X=5,
17-1.2X+1.2X=5+1.2X,
5+1.2X-5=17-5,
1.2X=12,
1.2X÷1.2=12÷1.2,
X=10;
(4)
4 |
5 |
1 |
4 |
1 |
2 |
1 |
20 |
1 |
5 |
1 |
2 |
1 |
20 |
1 |
5 |
1 |
2 |
1 |
2 |
1 |
20 |
1 |
2 |
1 |
20 |
1 |
2 |
1 |
5 |
1 |
20 |
1 |
2 |
1 |
20 |
1 |
5 |
1 |
20 |
1 |
2 |
3 |
20 |
1 |
2 |
3 |
20 |
x=
3 |
10 |
点评:本题主要考查了等式的性质,解答时要注意等号对齐.
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