题目内容
(1)5.63×6.34+0.563×36.6=
(2)1240×3.8+124×63-12.4×10=
(3)已知B=
A=
,那么A×B=;
(4)已知△÷△=□△+△=○△-△=☆□+○+☆=11.4,那么:△=
56.3
56.3
;(2)1240×3.8+124×63-12.4×10=
12400
12400
;(3)已知B=
| ||
1992个0 |
| ||
1992个0 |
(4)已知△÷△=□△+△=○△-△=☆□+○+☆=11.4,那么:△=
5.2
5.2
.分析:(1)把原式变形为56.3×0.634+56.3×0.366,运用乘法分配律简算;
(2)原式变为1240×3.8+1240×6.3-1240×0.1,运用乘法分配律简算;
(3)原式变为:
,进一步计算即可;
(4)把三个算式的两边分别相加,得=△÷△+△+△+△-△=1+2△,即1+2△=11.4,从而得出△的值.
(2)原式变为1240×3.8+1240×6.3-1240×0.1,运用乘法分配律简算;
(3)原式变为:
,进一步计算即可;
(4)把三个算式的两边分别相加,得=△÷△+△+△+△-△=1+2△,即1+2△=11.4,从而得出△的值.
解答:解:(1)5.63×6.34+0.563×36.6,
=56.3×0.634+56.3×0.366,
=56.3×(0.634+0.366),
=56.3;
(2)1240×3.8+124×63-12.4×10,
=1240×3.8+1240×6.3-1240×0.1,
=1240×(3.8+6.3-0.1),
=1240×10,
=12400;
(3)
×
,
=
=
(4))□+〇+☆,
=△÷△+△+△+△-△,
=1+2△,
=11.4,
所以2△=10.4,因此△=5.2;
故答案为:56.3,12400,,5.2.
=56.3×0.634+56.3×0.366,
=56.3×(0.634+0.366),
=56.3;
(2)1240×3.8+124×63-12.4×10,
=1240×3.8+1240×6.3-1240×0.1,
=1240×(3.8+6.3-0.1),
=1240×10,
=12400;
(3)
| ||
1992个0 |
| ||
1992个0 |
=
=
(4))□+〇+☆,
=△÷△+△+△+△-△,
=1+2△,
=11.4,
所以2△=10.4,因此△=5.2;
故答案为:56.3,12400,,5.2.
点评:认真观察算式,根据数字特点,灵活简算.
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