题目内容
解方程 25%x= ![]() | x+120%x=![]() | 15%x-3×5=0. |
解:(1)25%x=
,
x=
,
x÷
=
÷
,
x=
;
(2)x+120%x=
,
x=
,
x÷
=
÷
,
x=
;
(3)15%x-3×5=0,
0.15x-15=0,
0.15x-15+15=0+15,
0.15x=15,
0.15x÷0.15=15÷0.15,
x=100.
分析:(1)先把左边看作
x,再利用等式的性质两边同时除以
,即可解答;
(2)先计算左边的得数
x=
,根据等式的性质,先把两边同除以
,即可解答;
(3)先计算3×5得15,根据等式的性质,两边同时加上15,再根据等式的性质,两边同时0.15,即可解答;
点评:此题考查了利用等式的性质解方程的方法的灵活应用.
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x=
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(2)x+120%x=
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x=
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(3)15%x-3×5=0,
0.15x-15=0,
0.15x-15+15=0+15,
0.15x=15,
0.15x÷0.15=15÷0.15,
x=100.
分析:(1)先把左边看作
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(2)先计算左边的得数
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(3)先计算3×5得15,根据等式的性质,两边同时加上15,再根据等式的性质,两边同时0.15,即可解答;
点评:此题考查了利用等式的性质解方程的方法的灵活应用.
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