题目内容
(1)7.2×1.43÷
÷1.1
(2)0.125×76.8+12.5×0.132+1.25
(3)9
+99
+999
+9999
+99999
(4)
+
+
+
+
+
+
.
4 |
5 |
(2)0.125×76.8+12.5×0.132+1.25
(3)9
2 |
5 |
2 |
5 |
2 |
5 |
2 |
5 |
2 |
5 |
(4)
1 |
2 |
1 |
4 |
1 |
8 |
1 |
16 |
1 |
32 |
1 |
64 |
1 |
128 |
分析:(1)从左向右进行计算即可,
(2)运用乘法的分配律进行简算,
(3)原式=9+
+99+
+999+
+9999+
+99999+
,再运用加法的结合律进行简算,
(4)通过仔细观察,此算式中的每个分数都拆成两个分数相减的形式,然后通过加、减相互抵消,得出结果.
(2)运用乘法的分配律进行简算,
(3)原式=9+
2 |
5 |
2 |
5 |
2 |
5 |
2 |
5 |
2 |
5 |
(4)通过仔细观察,此算式中的每个分数都拆成两个分数相减的形式,然后通过加、减相互抵消,得出结果.
解答:解:(1)7.2×1.43÷
÷1.1,
=10.296÷
÷1.1,
=12.87÷1.1,
=11.7;
(2)0.125×76.8+12.5×0.132+1.25,
=0.125×76.8+0.125×13.2+0.125×10,
=0.125×(76.8+13.2+10),
=0.125×100,
=12.5;
(3)9
+99
+999
+9999
+99999
,
=9+
+99+
+999+
+9999+
+99999+
,
=9+99+999+9999+99999+
×5,
=9+99+999+9999+99999+2,
=(9+1)+(99+1)+(999+1)+(9999+1)+(99999+1)-5+2,
=10+100+1000+10000+100000-3,
=111110-3,
=1111107;
(4)
+
+
+
+
+
+
,
=1-
+
-
+
-
+
-
+
-
+
-
+
-
,
=1-
,
=
.
4 |
5 |
=10.296÷
4 |
5 |
=12.87÷1.1,
=11.7;
(2)0.125×76.8+12.5×0.132+1.25,
=0.125×76.8+0.125×13.2+0.125×10,
=0.125×(76.8+13.2+10),
=0.125×100,
=12.5;
(3)9
2 |
5 |
2 |
5 |
2 |
5 |
2 |
5 |
2 |
5 |
=9+
2 |
5 |
2 |
5 |
2 |
5 |
2 |
5 |
2 |
5 |
=9+99+999+9999+99999+
2 |
5 |
=9+99+999+9999+99999+2,
=(9+1)+(99+1)+(999+1)+(9999+1)+(99999+1)-5+2,
=10+100+1000+10000+100000-3,
=111110-3,
=1111107;
(4)
1 |
2 |
1 |
4 |
1 |
8 |
1 |
16 |
1 |
32 |
1 |
64 |
1 |
128 |
=1-
1 |
2 |
1 |
2 |
1 |
4 |
1 |
4 |
1 |
8 |
1 |
8 |
1 |
16 |
1 |
16 |
1 |
32 |
1 |
32 |
1 |
64 |
1 |
64 |
1 |
128 |
=1-
1 |
128 |
=
127 |
128 |
点评:此题考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算定律进行简便计算.
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