摘要:5.如图.已知Rt△ABC中.AC=3.BC= 4.过直角顶点C作CA1⊥AB.垂足为A1.再过A1作A1C1⊥BC.垂足为C1.过C1作C1A2⊥AB.垂足为A2.再过A2作A2C2⊥BC.垂足为C2.-.这样一直做下去.得到了一组线段CA1.A1C1..-.则CA1= .
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C4A5 | A5C5 |
如图,已知Rt△ABC中,AC=3,BC=4,过直角顶点C作CA1⊥AB,垂足为A1,再过A1作A1C1⊥BC,垂足为C1,过C1作C1A2⊥AB,垂足为A2,再过A2作A2C2⊥BC,垂足为C2,…,这样一直做下去,得到了一组线段CA1,A1C1,C1A2,…,则CA1= ,
= .
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