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已知,矩形ABCD中,延长BC至E,使BE = BD,F为DE的中点,连结AF、CF.(1)若AB = 3,AD = 4,求CF的长;(2)求证:∠ADB = 2∠DAF.
已知,矩形ABCD中,延长BC至E,使BE = BD,F为DE的中点,连结AF、CF.
(1)若AB = 3,AD = 4,求CF的长;
(2)求证:∠ADB = 2∠DAF.