摘要:从而CD⊥平面PBD.BE平面PBD.∴ CD⊥BE.∴BE⊥平面PCD.------------------------8分
网址:http://m.1010jiajiao.com/timu_id_537305[举报]

(I)求证:CD⊥平面PBD;
(II)求二面角A-BE-D的余弦值.
如图,四棱锥P-ABCD中,PB⊥底面ABCD.底面ABCD为直角梯形,∠ABC=90°,AD∥BC,AB=AD=PB,BC=2AD.点E在棱PA上,且PE=2EA.
(I)求证:CD⊥平面PBD;
(II)求二面角A-BE-D的余弦值.
查看习题详情和答案>>
如图,四棱锥P-ABCD中,PB⊥底面ABCD.底面ABCD为直角梯形,∠ABC=90°,AD∥BC,AB=AD=PB,BC=2AD.点E在棱PA上,且PE=2EA.
(I)求证:CD⊥平面PBD;
(II)求二面角A-BE-D的余弦值.
查看习题详情和答案>>
(I)求证:CD⊥平面PBD;
(II)求二面角A-BE-D的余弦值.
