摘要:1.在△ABC中.已知cosA =.sinB =.则cosC的值为----(A) A B C D 解:∵C = p - ∴cosC = - cos 又∵AÎ ∴sinA = 而sinB = 显然sinA > sinB ∴A > B 即B必为锐角 ∴ cosB = ∴cosC = - cos = sinAsinB - cosAcosB =
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