摘要:A. B.3-2 C.5+ D.-1-2[标准答案]
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已知△ABC三顶点A(1,2),B(3,6),C(5,2),M为AB中点,N为AC中点,则中位线MN所在直线方程为( )
A.2x+y-8=0 B.2x-y+8=0
C.2x+y-12=0 D.2x-y-12=0
查看习题详情和答案>>定义集合A-B={x|x∈A且x∉B},若集合A={1,2,3,4},集合B={1,2,-5,-7},则A-B=
- A.{1,2}
- B.{3,4}
- C.{-5,-7}
- D.{1,2,3,4,-5,-7}