摘要: 化学反应N2+3H2=2NH3的能量变化如图所示.该反应的热化学方程式是 A.N2(g)+3H2(g)=2NH3(1); △H=2kJ·mol-1 B. N2(g)+3H2(g)=2NH3(g); △H=2(b-a)kJ·mol-1 C.N2(g)+H2(g)=NH3(1); △H=kJ·mol-1 D. N2(g)+H2(g)=NH3(g);△H=(a+b)kJ·mol-1
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化学反应N2+3H2?2NH3的能量变化如图所示,该反应的热化学方程式是( )
A、N2(g)+3H2(g)?2NH3(l);△H=2(a-b-c) kJ/mol | ||||
B、N2(g)+3H2(g)?2NH3(g);△H=2(b-a) kJ/mol | ||||
C、
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D、
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化学反应N2+3H2→2NH3的能量变化如图所示,该反应的热化学方程式是( )
A、N2(g)+H2(g)→NH3(1)-46 kJ | B、N2(g)+H2(g)→NH3(g)-454 kJ | C、N2(g)+3 H2(g)→2 NH3(g)+92 kJ | D、N2(g)+3 H2(g)→2 NH3(1)+431.3 kJ |