摘要： 为发展旅游经济.我市某景区对门票采用灵活的售票方法吸引游客.门票定价为50元/人.非节假日打a折售票.节假日按团队人数分段定价售票.即m人以下(含m人)的团队按原价售票,超过m人的团队.其中m人仍按原价售票.超过m人部分的游客打b折售票.设某旅游团人数为x人.非节假日购票款为(元).节假日购票款为(元)..与x之间的函数图象如图8所示. (1)观察图象可知:a＝ ,b＝ ,m＝ , (2)直接写出.与x之间的函数关系式, (3)某旅行社导游王娜于5月1日带A团.5月20日带B团都到该景区旅游.共付门票款1900元.A.B两个团队合计50人.求A.B两个团队各有多少人? [答案] (1)················································ 3分 (2),······················································································································ 4分 .································································································ 6分 (3)设A团有n人.则B团有(50-n)人. 当0≤n≤10时. 解之.得n＝20.这与n≤10矛盾.··································································· 7分 当n＞10时.·························································· 8分 解之.得.n＝30.··································································································· 9分 ∴50-30＝20 答:A团有30人.B团有20人. 10分

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