摘要:化学反应N2+3H2 = 2NH3的能量变化如图所示.该反应的热化学方程式是( ) A.N2(g)+3H2(g) = 2NH3(l), ⊿H = 2kJ/mol B.N2(g)+3H2(g) = 2NH3(g), ⊿H = 2(b-a)kJ/mol C.N2(g)+H2(g)=NH3(l) , ⊿H = kJ/mol D.N2(g)+H2(g) =NH3(g), ⊿H = (a+b)kJ/mol

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