摘要:15.化简式计算: 计算:. 已知x=2-.y=2+. 求的值. [应用与探究]
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先化简,再计算:
(1)4xy-(2x2+5xy-y2)+2(x2+3xy),其中|x+2|+(y-
)2=0
(2)
x-2(x-
y2)-(
x-
y2),其中x=-2,y=
(3)5x3y-3[-x2y+2(x3y-
x2y)],其中x=2,y=-1.
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(1)4xy-(2x2+5xy-y2)+2(x2+3xy),其中|x+2|+(y-
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(2)
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(3)5x3y-3[-x2y+2(x3y-
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