摘要:3.用换元法解方程2x-3x2+4+1=0可设y = .从而把方程化为 .
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用换元法解方程2
+x-2=3,设
=y,则原方程化为关于y的整式方程是( )
| x-2 |
| x-2 |
| A、y2+2y+3=0 |
| B、y2+2y-3=0 |
| C、2y2+y-3=0 |
| D、2y2+y+3=0 |
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| x-2 |
| x-2 |
| A、y2+2y+3=0 |
| B、y2+2y-3=0 |
| C、2y2+y-3=0 |
| D、2y2+y+3=0 |