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若(1＋mx)6＝a0＋a1x＋a2x2＋…＋a6x6，且a1＋a2＋a3＋a4＋a5＋a6＝63，则实数m的值为
1
－1
－3
1或－3
若(1＋mx)6＝a0＋a1x＋a2x2＋…＋a6x6，且a1－a2＋a3－a4＋a5－a6＝－63，则实数m的值为________．