摘要:A={x∣x=2n,n∈N*},B={x∣x=3n,n∈N*},C={x∣x=4n-2,n∈N*},则∩B= .
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设M={x│x=2n+1,n∈N},Q={x│x=3n+1,n∈N},则M∩Q等于
- A.{x│x=5n+1,n∈N}
- B.{x│x=6n+1,n∈N}
- C.{x│x=6n+2,n∈N}
- D.{x│x=5n+2,n∈N}
设M={x | x=2n,n∈N},P={x | x=3n,n∈N},则M∩P等于
- A.{x | x=n,n∈N}
- B.{x | x=5n,n∈N}
- C.{x | x=12n,n∈N}
- D.{x | x=6n,n∈N}