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函数y=log[(1-x)(x+3)]的递减区间是( )?
A.(-3,-1) B.(-∞,-1)?
C.(-∞,-3) D.(-1,+∞)
函数y=log(x2-3x+2)的递增区间是
A.(-∞,1)
B.(2,+∞)
C.(-∞,)
D.(,+∞)
函数y=log(x2-6x+17)的值域是 ( )
函数y=log[(1-x)(x+3)]的递减区间是
(-3,-1)
(-∞,-1)
(-∞,-3)
(-1,+∞)
A.y=log(x+1)
B.y=log2
C.y=log3
D.y=log (x2-4x+5)