摘要：5．甲醇质子交换膜燃料电池中将甲醇蒸气转化为氢气的两种反应原理是 ①CH3OH(g)+H2O(g) = CO2(g)+3H2(g),DH = + 49.0 kJ·mol-1 ②CH3OH(g)+1/2O2(g) = CO2(g)+2H2(g),DH =-192.9 kJ·mol-1 下列说法正确的是( ) (A)CH3OH的燃烧热为192.9 kJ·mol-1 (B)反应①中的能量变化如图所示 (C)CH3OH转变成H2的过程一定要吸收能量 (D)根据②推知反应:CH3OH(l)+1/2O2(g) = CO2(g)+2H2(g)的H＞-192.9 kJ·mol-1

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