摘要: .已知在1×105Pa.298K条件下.2mol氢气完全燃烧生成水蒸气放出484kJ热量.下列热化学方程式正确的是 A.2H2(g)+O2(g)=2H2O(g) △H=+484kJ·mol-1 B.2H2(g)+O2(g)=2H2O(l) △H=-484kJ·mol-1 C.H2(g)+1/2O2(g)=H2O(g) △H=+242kJ·mol-1 D.H2O(g)= H2(g) +1/2O2 (g) △H=+242kJ·mol-1

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