摘要:3.燃烧2 g乙醇.生成二氧化碳气体和液态水.经测定放出的热量为Q.则乙醇燃烧的热化学方程式书写正确的是( ) A.C2H5OH(1)+3O2(g)=2CO2(g)+3H2O(1) △H = -23Q KJ/mol B.C2H5OH(1)+3O2(g)=2CO2(g)+3H2O(1) △H = - Q /23 KJ / mol C.1/2 C2H5OH(1)+3/2O2(g)=CO2(g)+3/2H2O(1) △H = -QKJ /mol D.C2H5OH(1)+3O2(g)=2CO2(g)+3H2O(1) △H = +23Q KJ/mol

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