摘要: 10分 解:设此烃的的分子式为CxHy 则有CxHy + O2 x CO2 + H2O (液) △V ······················1分 1 x+ x 1+ 10mL 50mL 25mL 讨论: (1) 若O2 过量. 则1 : 10 mL= : 25mL ·····················3分 解得:y=6, 即该烃可能为C­2H6.C3H6和C4H6 ·····················5分 : 50mL = : 25mL ···················7分 解得: y=4x-8 ···················8分 ① x=1. y= -4 ② x=2, y=0 ③ x=3, y=4 该烃为C3H4 ④ x=4, y=8 该烃为 C4H8 ··································10分

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