摘要:23. (1)设该烃的化学式为CxHy CxHy +(x+y/4)O2 xCO2 + y/2H2O △V 1 y/4-1 10mL 65 mL- 解之得:y = 6 (2)CH3-CH=CH2 .当该气态烃为炔烃时.应为C4H6.若10mL在50mLO2中燃烧.氧气量不足.与题设不符.

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