摘要:解:(1)E=BLv=1.0×0.5×5.4=2.7v 由右手定则知:棒上感应电流方向:A→B (2)R1R2/(R1+R2)=2Ω I=E/(+r)=2.7/(2+1)=0.9A U=I=0.9×2=1.8v (3)∵棒匀速 ∴==BIL=1.0×0.9×0.5=0.45N =v=2.43W (4)=IE(或=I2+I2r或=)=0.9×2.7=2.43W

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