摘要:(1)∵I=.∴R2===30Ω----------------------------------------- (2)∵P=IU1=0.2A×12V=2.4W----------------------------------------------- (3)∵灯泡L的电阻RL===60Ω--------------------------------------- 灯泡L’的电阻RL’===20Ω----------------------------------------- ∴R总=RL+ RL’=80Ω 当灯泡L’接入电路时.I总===0.225A<0.3A ∴L’不能正常发光.-----------------------------------------------------

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