ÌâÄ¿ÄÚÈÝ

Èçͼ£¬ÊÇ»ØÐý¼ÓËÙÆ÷µÄÔ­ÀíʾÒâͼ£¬ÆäºËÐIJ¿·ÖÊÇÁ½¸öDÐνðÊôºÐ£¬ÔÚ¼ÓËÙ´øµçÁ£×Óʱ£¬Á½½ðÊôºÐÖÃÓڴŸÐӦǿ¶È´óСΪBµÄÔÈÇ¿´Å³¡ÖУ¬²¢·Ö±ðÓë¸ßƵµÄ½»Á÷µçÏàÁ¬£¬ÒÑÖª¼ÓËÙµçѹΪU£¬DÐνðÊôºÐµÄ°ë¾¶ÎªR£¬Á½ºÐÖ®¼äµÄÏÁ·ê¾àÀëΪd£¬ÈôO´¦Á£×ÓÔ´²úÉúÖÊÁ¿Îªm¡¢µçºÉÁ¿Îª+qµÄÖÊ×ÓÔÚ¼ÓËÙÆ÷Öб»¼ÓËÙ£¨ºöÂÔÁ£×ÓÖÊÁ¿±ä»¯£¬²»¼ÆÖØÁ¦£©£¬ÔòÏÂÁÐÅжÏÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®ÖÊ×Ó¼ÓËٶȵÄ×î´ó¶¯ÄÜΪ
q2B2R2
2m
B£®ÖÊ×Óÿ´Î¼ÓËÙºó¾­¹ýDÐκмäµÄÏÁ·ì¹ìµÀ°ë¾¶ÊǼÓËÙÇ°¹ìµÀ°ë¾¶µÄ2±¶
C£®ÖÊ×ÓÔڵ糡Óë´Å³¡ÖÐÔ˶¯µÄ×Üʱ¼äΪt=
¦ÐBR2
2U
+d
2mN
qU
D£®²»¸Ä±ä´Å¸ÐӦǿ¶ÈBºÍ½»±äµçÁ÷µÄƵÂÊf£¬¸Ã»ØÐý¼ÓËÙ¶ÈÆ÷²»ÄÜÓÃÓÚ¼ÓËÙ뮺Ë

A¡¢ÓÉqvmB=
mvm2
R
µÃR=
mvm
qB
?vm=
BqR
m
£¬Á£×Ó»ñµÃµÄ×î´ó¶¯ÄÜEkm=
1
2
mvm2=
q2B2R2
2m
£¬¹ÊAÕýÈ·£»
B¡¢Óɶ¯Äܶ¨Àí¿ÉµÃ¡÷Ek=qU£¬¿É֪ÿ´Î¼ÓËÙ¶¯ÄÜÔö¼ÓÏàͬ£¬µ«ËÙ¶ÈÔö¼Ó²»ÊÇÏàͬ£¬¸ù¾ÝR=
mv
Bq
£¬¿ÉÖª£¬ÏÁ·ì¹ìµÀ°ë¾¶²»ÊǼÓËÙÇ°¹ìµÀ°ë¾¶µÄ2±¶£¬¹ÊB´íÎó£»
C¡¢ÉèÁ£×Ó¼ÓËٵĴÎÊýΪN£¬Óɶ¯Äܶ¨Àí¿ÉµÃ£ºNqU=Ekm=
q2B2R2
2m
?N=
qB2R2
2mU
£¬¹ÊÔڴų¡ÖÐÔ˶¯µÄʱ¼äΪ£ºtB=
N
2
T=
qB2R2
4mU
¡Á
2¦Ðm
Bq
=
¦ÐBR2
2U
£¬Ôڵ糡ÖÐÔȼÓËÙÔ˶¯£ºNd=
1
2
qU
md
t2E?tE=d
2mN
qU
£¬¹ÊÔÚµç´Å³¡ÖÐÔ˶¯µÄ×Üʱ¼äΪ£ºt=
¦ÐBR2
2U
+d
2mN
qU
£¬¹ÊCÕýÈ·£»
D¡¢¼ÓËÙÁ£×ÓµÄÖÜÆÚµÈÓÚ½»±äµçÁ÷µÄÖÜÆÚ£¬¹Ê²»¸Ä±ä´Å¸ÐӦǿ¶ÈBºÍ½»±äµçÁ÷µÄƵÂÊf£¬¸Ã»ØÐý¼ÓËÙ¶ÈÆ÷²»ÄÜÓÃÓÚ¼ÓËÙ뮺ˣ¬¹ÊDÕýÈ·£»
¹ÊÑ¡£ºACD£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø