题目内容
(本题12分) 如图所示,匀强电场中A、B、C三点构成一个直角三角形,AC边在同一个等势面上,BC边长,
。把电荷量
的点电荷由A点移动到B点,电场力做功
,取B点的电势为零,求:
(1)A点的电势;
(2)匀强电场的大小,并在图中画出场强的方向。
【答案】
![](http://thumb.1010pic.com/pic6/res/gzwl/web/STSource/2012052720273204252209/SYS201205272028303706712523_DA.files/image001.png)
![](http://thumb.1010pic.com/pic6/res/gzwl/web/STSource/2012052720273204252209/SYS201205272028303706712523_DA.files/image002.png)
![](http://thumb.1010pic.com/pic6/res/gzwl/web/STSource/2012052720273204252209/SYS201205272028303706712523_DA.files/image003.jpg)
|
![](http://thumb.1010pic.com/pic6/res/gzwl/web/STSource/2012052720273204252209/SYS201205272028303706712523_DA.files/image001.png)
![](http://thumb.1010pic.com/pic6/res/gzwl/web/STSource/2012052720273204252209/SYS201205272028303706712523_DA.files/image002.png)
![](http://thumb.1010pic.com/pic6/res/gzwl/web/STSource/2012052720273204252209/SYS201205272028303706712523_DA.files/image003.jpg)
![](http://thumb.1010pic.com/pic6/res/gzwl/web/STSource/2012052720273204252209/SYS201205272028303706712523_DA.files/image004.png)
(2)场强垂直于AC边,方向如图所示[来源:学|科|网Z|X|X|K]
【解析】略
![](http://thumb2018.1010pic.com/images/loading.gif)
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