题目内容
如图所示,轻杆BO一端装在铰链上,铰链固定在竖直墙上,另一端装一轻滑轮,重为G的物体用细绳经滑轮系于墙上A点,系统处于平衡状态,若将A点沿竖直墙向上缓慢移动少许,设法使系统重新平衡,则细绳所受拉力F1和轻杆所受压力F2大小变化情况是
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250004199102547.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250004199102547.jpg)
A.F1变小 | B.F1不变 | C.F2变小 | D.F2不变 |
BC
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250004199254497.jpg)
试题分析:以O为研究对象进行受力分析,根据平衡关系画出几何图形,根据各力的性质及变化可由力的合成得出F的变化。由于AOG为同一根绳,所以绳的拉力大小相等所以
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825000419941460.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825000420112336.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825000420112336.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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