题目内容
(10分)在做“用单摆测定重力加速度”的实验时,如果已知摆球直径为2.00厘米,让刻度尺的零点对准摆线的悬点,摆线竖直下垂,如下图所示,那么单摆摆长是________ m。如果测定了40次全振动的时间如下图中秒表所示,那么秒表读数是_________ s,
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/2014082413411715873946.png)
用游标卡尺分别测量一根金属管的外径和内径,其结果如图所示。则金属管的外径是______cm,经过计算得到金属管厚度是________cm。![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241341172367177.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/2014082413411715873946.png)
用游标卡尺分别测量一根金属管的外径和内径,其结果如图所示。则金属管的外径是______cm,经过计算得到金属管厚度是________cm。
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241341172367177.jpg)
0.8740m 或0.874m (2分) 、75. 2s(3分)、 2.66cm(2分)、0.31cm(3分)
由图可知,单摆摆长为
=88.40cm-
=88.40-1.00=87.40cm=0.8740m;由图知分针读数1min=60s,秒针读数15.2s,秒表读数是60+15.2=75.2s;由图知:主尺读数2.6cm=26mm,游标尺读数6
0.1=0.6mm,金属管的外径是26mm+0.6mm=26.6mm=2.66cm;由图知:主尺读数2.0cm=20mm,游标尺读数4
0.1=0.4mm,金属管的内径是20mm+0.4mm=20.4mm=2.04cm;金属管厚度d=
cm。
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134117252280.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134117299429.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134117330214.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134117330214.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134117408843.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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