ÌâÄ¿ÄÚÈÝ

Ôø¾­Á÷ÐйýÒ»ÖÖÏò×ÔÐгµ³µÍ·µÆ¹©µçµÄСÐͽ»Á÷·¢µç»ú£¬Í¼3-7-2¼×ΪÆä½á¹¹Ê¾Òâͼ.ͼÖÐN¡¢SÊÇÒ»¶Ô¹Ì¶¨µÄ´Å¼«£¬abcdÊǹ̶¨ÔÚתÖáÉϵľØÐÎÏß¿ò.תÖá¹ýbcµÄÖеã,Óëab±ßƽÐУ¬ ËüµÄÒ»¶ËÓÐÒ»°ë¾¶r0=1.0 cmµÄĦ²ÁСÂÖ£¬Ð¡ÂÖÓë×ÔÐгµ³µÂֵıßÔµÏà½Ó´¥£¬Èçͼ3-7-2ÒÒËùʾ.µ±³µÂÖת¶¯Ê±£¬ÒòĦ²Á¶ø´ø¶¯Ð¡ÂÖת¶¯£¬´Ó¶øʹÏß¿òÔڴż«¼äת¶¯.ÉèÏß¿òÓÉN=800Ôѵ¼ÏßȦ×é³É£¬Ã¿ÔÑÏßȦµÄÃæ»ýS=20 cm2£¬´Å¼«¼äµÄ´Å³¡¿ÉÊÓΪÔÈÇ¿´Å³¡£¬´Å¸ÐӦǿ¶ÈB=0.010 T£¬×ÔÐгµ³µÂֵİ뾶R1=35 cm£¬Ð¡³ÝÂֵİ뾶R2=4.0 cm£¬´ó³ÝÂֵİ뾶R3=10.0 cm£¨¼ûͼ3-7-2ÒÒ£©.ÏÖ´Ó¾²Ö¹¿ªÊ¼Ê¹´ó³ÝÂÖ¼ÓËÙת¶¯£¬ÎÊ´ó³ÝÂֵĽÇËÙ¶ÈΪ¶à´óʱ²ÅÄÜʹ·¢µç»úÊä³öµçѹµÄÓÐЧֵU=3.2 V?£¨¼Ù¶¨Ä¦²ÁСÂÖÓë×ÔÐгµ³µÂÖÖ®¼äÎÞÏà¶Ô»¬¶¯£©

ͼ3-7-2

½âÎö£ºÏßȦÔÚÔÈÇ¿´Å³¡ÖÐÔÈËÙת¶¯Ê±²úÉúÕýÏÒ½»±äµçÁ÷£¬ÏßȦÖиÐÓ¦µç¶¯ÊƵÄÓÐЧֵEºÍÊä³öµçѹµÄÓÐЧֵUÏàµÈ£¬¶øÏßȦÖиÐÓ¦µç¶¯ÊƵÄ×î´óÖµEm=E=NBS¦Ø0.ÓÉÌâÉèÊý¾Ý¿ÉÇó¦Ø0£¬ÔÙÀûÓø÷ÖÖ´«¶¯ÖÐÏßËٶȡ¢½ÇËٶȼ°°ë¾¶µÄ±ÈÀý¹Øϵ£¬¼´¿ÉÇó³ö´ó³ÝÂֵĽÇËٶȦØ3.

ÉèÏßȦ£¨»òĦ²ÁСÂÖ£©¡¢Ð¡³ÝÂÖ£¨»ò×ÔÐгµ³µÂÖ£©¡¢´ó³ÝÂֵĽÇËٶȷֱðΪ¦Ø0¡¢¦Ø2ºÍ¦Ø3£¬ÔòÓÐEm=NBS¦Ø0                                                                 ¢Ù

Em=U                                                                     ¢Ú

                                                                     ¢Û

                                                                     ¢Ü

½â¢Ù¢Ú¢Û¢ÜʽµÃ£º¦Ø3=3.23 rad/s.

´ð°¸£º3.23 rad/s

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø