题目内容
如图所示,一细木棍AB斜靠在地面与竖直墙壁之间。木棍AB与水平面之间的夹角为450。A点到地面的距离为1m。已知重力加速度为10m/s2。空气阻力不计,现一跳蚤从竖直墙上距地面0.8m的C点以水平速度v0跳出,要到达细木棍上,水平速度v0至少为( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250019529321882.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250019529321882.jpg)
A.1m/s | B.2m/s | C.2.5m/s | D.![]() |
B
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250019529633287.jpg)
试题分析: 设速度为v0时运动轨迹恰好与AB相切,则运动的位移满足:
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001952978819.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001952994469.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825001953072620.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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