ÌâÄ¿ÄÚÈÝ

ijѧÉúÀûÓÃ×ÔÐгµÄÚÌ¥¡¢´òÆøͲ¡¢Î¶ȴ«¸ÐÆ÷ÒÔ¼°¼ÆËã»úµÈ×°ÖÃÑо¿×ÔÐгµÄÚÌ¥´òÆø¡¢´òÆø½áÊø¡¢Í»È»°ÎµôÆøÃÅо·ÅÆøÓë·ÅÆøºó¾²ÖÃÒ»¶Îʱ¼äµÄÕû¸ö¹ý³ÌÖÐÄÚÄܱ仯Çé¿ö£¬³µÌ¥ÄÚ    ÆøÌåζÈËæʱÎʱ仯µÄÇé¿öÈçͼËùʾ¡£¿É»ñÈ¡µÄÐÅÏ¢ÊÇ£¨   £©

A£®´Ó¿ªÊ¼´òÆøµ½´òÆø½áÊøµÄ¹ý³ÌÖÐÓÉÓÚÆøÌå¶ÔÍâ×ö¹¦£¬ÄÚÄÜѸËÙÔö´ó

B£®´òÆø½áÊøµ½°Î³öÆøÃÅоǰÓÉÓÚÆøÌå¶ÔÍâ×ö¹¦£¬ÆäÄÚÄÜ»ºÂý¼õÉÙ

C£®°ÎµôÆøÃÅоºóÓÉÓÚÆøÌå³å³ö¶ÔÍâ×ö¹¦£¬ÆäÄÚÄܼ±¾ç¼õÉÙ

D£®·ÅÆøºó¾²ÖÃÒ»¶Îʱ¼äÓÉÓÚÔٴζÔÆøÌå×ö¹¦£¬ÆøÌåÄÚÄÜÔö´ó

C


½âÎö:

´òÆøÊÇÍâ½ç¶ÔÆøÌå×ö¹¦£¬A´í£»·ÅÆøÊÇÆøÌå¶ÔÍâ×ö¹¦£¬·ÅÆøºÜ¿ì£¬ÄÚÄܼ±¾ç¼õС£¬C¶Ô¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

 £¨1£©Ä³Ñ§ÉúÀûÓÃ×ÔÐгµÄÚÌ¥¡¢´òÆøͲ¡¢Î¶ȴ«¸ÐÆ÷ÒÔ¼°¼ÆËã»úµÈ×°ÖÃÑо¿×ÔÐгµÄÚÌ¥´òÆø¡¢´òÆø½áÊø¡¢Í»È»°ÎµôÆøÃÅо·ÅÆøÓë·ÅÆøºó¾²ÖÃÒ»¶Îʱ¼äµÄÕû¸ö¹ý³ÌÖÐÆøÌåÄÚÄܵı仯Çé¿ö£¬Ëû»æ³öÁ˳µÌ¥ÄÚÆøÌåζÈËæʱ¼ä±ä»¯µÄͼÏߣ¬ÈçͼËùʾ¡£¸ù¾ÝͼÏßÌṩµÄÐÅÏ¢£¬ÏÂÁÐÅжÏÕýÈ·µÄÊÇ________£¨½«ÏàÓ¦µÄ×Öĸ´úºÅÌîµ½ºáÏßÉÏ£©

A£®´Ó¿ªÊ¼´òÆøµ½´òÆø½áÊøµÄ¹ý³ÌÖÐÓÉÓÚÆø   

Ìå¶ÔÍâ×ö¹¦£¬ÄÚÄÜѸËÙÔö´ó

B£®´òÆø½áÊøµ½°Î³öÆøÃÅоǰÓÉÓÚÆøÌå¶ÔÍâ×ö¹¦£¬ÆäÄÚÄÜ»ºÂý¼õÉÙ

C£®°ÎµôÆøÃÅоºóÓÉÓÚÆøÌå³å³ö¶ÔÍâ×ö¹¦£¬ÆäÄÚÄܼ±¾ç¼õÉÙ

D£®·ÅÆøºó¾²ÖÃÒ»¶Îʱ¼äÓÉÓÚÔٴζÔÆøÌå×ö¹¦£¬ÆøÌåÄÚÄÜÔö´ó

£¨2£©¾ÙÊÀÖõÄ¿µÄ¹ú¼ÒÓÎÓ¾ÖÐÐÄ¡°Ë®Á¢·½¡±ÊǵÚ29½ì±±¾©°ÂÔË»áÓÎÓ¾¡¢ÌøË®¡¢»¨ÑùÓÎÓ¾µÄ±ÈÈü³¡¹Ý£¬¸ÃÖÐÐÄÓµÓг¤50m¡¢¿í25m¡¢Ë®Éî3m¡¢Ë®Î±£³Ö27¡ª28¡æ£¬¹²10ÌõÓ¾µÀµÄ¹ú¼Ê±ê×¼±ÈÈüÓÃÓÎÓ¾³Ø¡£ÒÑ֪ˮµÄĦ¶ûÖÊÁ¿M=1.8¡Á10-2kg/mol£¬ÃܶÈΪ1.0¡Á103kg/m3£¬°¢·ü¼ÓµÂÂÞ³£ÊýΪ6¡Á1023mol-1£¬µ±ÓÎÓ¾³Ø×¢Âúˮʱ£¬¹ÀËã³ØÖÐË®·Ö×ÓÊýÄ¿¡££¨½á¹û±£ÁôÁ½Î»ÓÐЧÊý×Ö£©

 

 

 

 

 

 

 

 

 

 £¨1£©Ä³Ñ§ÉúÀûÓÃ×ÔÐгµÄÚÌ¥¡¢´òÆøͲ¡¢Î¶ȴ«¸ÐÆ÷ÒÔ¼°¼ÆËã»úµÈ×°ÖÃÑо¿×ÔÐгµÄÚÌ¥´òÆø¡¢´òÆø½áÊø¡¢Í»È»°ÎµôÆøÃÅо·ÅÆøÓë·ÅÆøºó¾²ÖÃÒ»¶Îʱ¼äµÄÕû¸ö¹ý³ÌÖÐÆøÌåÄÚÄܵı仯Çé¿ö£¬Ëû»æ³öÁ˳µÌ¥ÄÚÆøÌåζÈËæʱ¼ä±ä»¯µÄͼÏߣ¬ÈçͼËùʾ¡£¸ù¾ÝͼÏßÌṩµÄÐÅÏ¢£¬ÏÂÁÐÅжÏÕýÈ·µÄÊÇ________£¨½«ÏàÓ¦µÄ×Öĸ´úºÅÌîµ½ºáÏßÉÏ£©

A£®´Ó¿ªÊ¼´òÆøµ½´òÆø½áÊøµÄ¹ý³ÌÖÐÓÉÓÚÆø   

Ìå¶ÔÍâ×ö¹¦£¬ÄÚÄÜѸËÙÔö´ó

B£®´òÆø½áÊøµ½°Î³öÆøÃÅоǰÓÉÓÚÆøÌå¶ÔÍâ×ö¹¦£¬ÆäÄÚÄÜ»ºÂý¼õÉÙ

C£®°ÎµôÆøÃÅоºóÓÉÓÚÆøÌå³å³ö¶ÔÍâ×ö¹¦£¬ÆäÄÚÄܼ±¾ç¼õÉÙ

D£®·ÅÆøºó¾²ÖÃÒ»¶Îʱ¼äÓÉÓÚÔٴζÔÆøÌå×ö¹¦£¬ÆøÌåÄÚÄÜÔö´ó

£¨2£©¾ÙÊÀÖõÄ¿µÄ¹ú¼ÒÓÎÓ¾ÖÐÐÄ¡°Ë®Á¢·½¡±ÊǵÚ29½ì±±¾©°ÂÔË»áÓÎÓ¾¡¢ÌøË®¡¢»¨ÑùÓÎÓ¾µÄ±ÈÈü³¡¹Ý£¬¸ÃÖÐÐÄÓµÓг¤50m¡¢¿í25m¡¢Ë®Éî3m¡¢Ë®Î±£³Ö27¡ª28¡æ£¬¹²10ÌõÓ¾µÀµÄ¹ú¼Ê±ê×¼±ÈÈüÓÃÓÎÓ¾³Ø¡£ÒÑ֪ˮµÄĦ¶ûÖÊÁ¿M=1.8¡Á10-2kg/mol£¬ÃܶÈΪ1.0¡Á103kg/m3£¬°¢·ü¼ÓµÂÂÞ³£ÊýΪ6¡Á1023mol-1£¬µ±ÓÎÓ¾³Ø×¢Âúˮʱ£¬¹ÀËã³ØÖÐË®·Ö×ÓÊýÄ¿¡££¨½á¹û±£ÁôÁ½Î»ÓÐЧÊý×Ö£©

 

 

 

 

 

 

 

 

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø