ÌâÄ¿ÄÚÈÝ
1£®Èçͼ¼×ËùʾÊÇÒ»ÖÖеĶÌ;´ú²½¹¤¾ß-µç¶¯Æ½ºâ³µ£¬±»³ÆΪվ×ÅÆïµÄµç¶¯³µ£¬Æä×î´óËٶȿɴï20km/h£¬Ä³Í¬Ñ§Îª²âÁ¿Ò»µç¶¯Æ½ºâ³µÔÚƽֱˮÄàÀïÃæÉÏÊܵ½µÄ×èÁ¦Çé¿ö£¬Éè¼ÆÁËÏÂÊöʵÑ飺½«ÊäÒºÓõÄ500mLËÜÁÏƿװÊÊÁ¿Ë®ºó£¬Á¬Í¬ÊäÒº¹ÜÒ»Æð°óÔÚƽºâ³µµÄ»¤ÊÖÉÏ£¬µ÷½ÚÊäÒº¹ÜµÄµÎË®Ëٶȣ¬Ä³µÎË®¸ÕÂäµØ¿ªÊ¼¼Æʱ£¬´ÓÏÂÒ»µÎË®¿ªÊ¼ÒÀ´Î¼ÆÊýΪ1¡¢2¡¢3¡£¬µ±µÚ50µÎË®¸ÕºÃÂäµØʱֹͣ¼Æʱ£¬²âµÃʱ¼äΪ25.0s£¬¸ÃͬѧÆïÉÏƽºâ³µºó£¬ÏȼÓËÙµ½Ä³Ò»Ëٶȣ¬È»ºó¹Ø±Õ¶¯Á¦£¬ÈÃƽºâ³µÑØ×ÅÖ±Ïß»¬ÐУ¬ÈçͼÒÒËùʾÊÇij´ÎʵÑéÖÐÔÚË®Äà·ÃæÉϵIJ¿·ÖË®µÎ¼°²â³öµÄ¼ä¾àÖµ£¨×ó²àÊÇÆðµã£¬µ¥Î»£ºm£©£¬ÒÑÖªµ±µØÖØÁ¦¼ÓËÙ¶Èg=9.8m/s2£¬Ôò¸ù¾Ý¸ÃͬѧµÄ²âÁ¿½á¹û¿ÉµÃ³ö£º£¨1£©Æ½ºâ³µ¾¹ý·ÃæÉÏÏàÁÚÁ½µÎË®¼äµÄʱ¼ä¼ä¸ôT=0.50s£»
£¨2£©Æ½ºâ³µ¼ÓËÙ¹ý³ÌµÄ¼ÓËٶȴóСa1=1.96m/s2£»
£¨3£©Éèƽºâ³µÔ˶¯¹ý³ÌÖÐËùÊÜ×èÁ¦µÄ´óСÊÇÈËÓë³µ×ÜÖØÁ¦µÄK±¶£¬ÔòK=5.3¡Á10-2£¨¼ÆËã½á¹û±£ÁôÁ½Î»ÓÐЧÊý×Ö£©
·ÖÎö ¸ù¾Ýij¶Îʱ¼äÄÚµÄƽ¾ùËٶȵÈÓÚÖмäʱ¿ÌµÄ˲ʱËٶȣ¬Çó³öDµãµÄËٶȣ»¸ù¾ÝÁ¬ÐøÏàµÈʱ¼äÄÚµÄλÒÆÖ®²îÊÇÒ»ºãÁ¿£¬Çó³ö¼ÓËٶȣ¬½áºÏÅ£¶ÙµÚ¶þ¶¨ÂÉÇó³ö×èÁ¦µÄ´óС£®
½â´ð ½â£º£¨1£©µ±µÚ50µÎË®¸ÕºÃÂäµØʱֹͣ¼Æʱ£¬²âµÃʱ¼äΪ25.0s£¬
ÔòÏàÁÚÁ½µÎË®¼äµÄʱ¼ä¼ä¸ôΪ£ºT=0.50s£»
£¨2£©ÔÚ¼ÓËٽ׶Σ¬Á¬ÐøÏàµÈʱ¼äÄÚµÄλÒÆÖ®²îΪ£º¡÷x=4m£¬
¸ù¾Ý¡÷x=aT2µÃ£ºa=$\frac{1.98+2.49-1.01-1.5}{{£¨2¡Á0.5£©}^{2}}$m/s2=1.96m/s2£®
£¨3£©ÔÚ¼õËٽ׶Σ¬¸ù¾Ý¡÷x=aT2£¬ÔËÓÃÖð²î·¨µÃ£º
a=$\frac{2.16+1.95-2.37-2.26}{4{¡Á£¨0.5£©}^{2}}$m/s2=-0.52m/s2£®
¸ù¾ÝÅ£¶ÙµÚ¶þ¶¨Âɵãºf=Kmg=ma
½âµÃ£ºK=$\frac{a}{g}$=5.3¡Á10-2£®
¹Ê´ð°¸Îª£º£¨1£©0.50£»£¨2£©1.96£»£¨3£©5.3¡Á10-2£®
µãÆÀ ÔÚË®Äà·ÃæÉϵIJ¿·ÖË®µÎÓëÖ½´øÎÊÌâÀàËÆ£¬ÕÆÎÕ´¦ÀíµÄ·½·¨£¬»á¸ù¾ÝË®µÎÐγɵÄͼÑùÇó½â˲ʱËٶȺͼÓËٶȣ¬¹Ø¼üÊÇÔȱäËÙÖ±ÏßÔ˶¯Á½¸öÖØÒªÍÆÂÛµÄÔËÓã®
A£® | λÒÆ | B£® | ÏßËÙ¶È | C£® | ½ÇËÙ¶È | D£® | ÖÜÆÚ |
A£® | bËùÐèÏòÐÄÁ¦×îС | |
B£® | b¡¢cµÄÖÜÆÚÏàͬÇÒ´óÓÚaµÄÖÜÆÚ | |
C£® | b¡¢cµÄÏòÐļÓËٶȴóСÏàµÈ£¬ÇÒ´óÓÚaµÄÏòÐļÓËÙ¶È | |
D£® | c¼ÓËÙ¿É×·ÉÏͬһ¹ìµÀÉϵÄb£¬b¼õËٿɵȺòͬһ¹ìµÀÉϵÄc |
A£® | F´óÓÚmg | |
B£® | FСÓÚmg | |
C£® | AÇò¿ÉÄÜÊÜ3¸öÁ¦£¬BÇò¿ÉÄÜÊÜ4¸öÁ¦ | |
D£® | ¼ô¶ÏAB¼äµÄÉþ£¬AÇòËùÊܺÏÍâÁ¦¿ÉÄܱ仯 |
A£® | ÈôF1¡¢F2ÖеÄÒ»¸öÔö´ó£¬F²»Ò»¶¨Ôö´ó | |
B£® | ÈôF1¡¢F2µÄ·½Ïò¸Ä±ä£¬FµÄ·½ÏòÒ²Ò»¶¨¸Ä±ä | |
C£® | ÈôÁ½¸ö¹²µãÁ¦µÄ¼Ð½ÇСÓÚ120¡ã£¬ÔòºÏÁ¦F´óСΪÁ½¸ö¹²µãÁ¦Á¦´óС֮ºÍ | |
D£® | ÈôF1¡¢F2Ôö´ó£¬FÒ²Ò»¶¨Ôö´ó |