题目内容
![](http://thumb.1010pic.com/pic3/upload/images/201406/113/adb21ede.png)
(1)电阻关系,R1:R2为
(2)若两个导体中的电流相等(不为零)时,电压之比U1:U2为
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有两个导体a、b,它们的伏安特性曲线如图所示,据此分析,正确的结论是( )
![](http://thumb.1010pic.com/pic3/upload/images/201411/187/5e509976.png)
![](http://thumb.1010pic.com/pic3/upload/images/201411/187/5e509976.png)
A、导体a的电阻较小 | B、导体a的电阻率较小 | C、导体b较长 | D、导体b较粗 |
用伏安法测电阻RX时的电路如图甲、乙两种接法,若用甲图接法测量值为R1若用乙图接法测量值为R2,下面说法中正确的是( )
![](http://thumb.1010pic.com/pic3/upload/images/201406/149/433e93d5.png)
![](http://thumb.1010pic.com/pic3/upload/images/201406/149/433e93d5.png)
A、R2>RX>R1 | B、R2<RX<R1 | C、RX>R1RX>R2 | D、RX<R1RX<R2 |